lst_remove(L;R)
Remove elements from list-value L that are
found in list-value R. This function does not remove duplicates that appear
multiple times in list-value L from the returned list-value.
Syntax
lst_remove(L;R)Input
| Argument | Type | Description |
|---|---|---|
L |
list-value | A list-value whose values will be removed according to values found in
list-value R |
D |
list-value | A list-value whose values will be used to remove values from list-value
L |
Return Value
Returns a single list-value that contains elements of list L that were not
found in list R. The list-value returned preserves any duplicate values in
list-value L that did not appear in list-value R.
Example
This example demonstrates how to use lst_remove(L;R) to eliminate elements
of a list-value based on the values in another list-value.
<block name="list_funs" list_a="{lst(1 2 3 4 'a')}" list_b="{lst(1 'a' 'b' 'c' 'd' 'a' 'b')}"> <base table="default.lonely"/> <willbe name="lst_remove" label="List Remove" value="'{lst_remove(@list_b;@list_a)}'"/> </block>
The list-value output from the lst_remove(L;R) function as used above:
Note: The value
b appears twice in list-value
L and does
not appear in list-value R. Therefore, it appears twice in the list-value
returned by the function.