unlst(L1 L2...LN)
Find the union of two or more list-values.
Syntax
unlst(L1 L2...LN)
Input
Argument | Type | Description |
---|---|---|
L |
list-value | A space-separated or comma-separated list of list-values whose union will be found |
Return Value
Returns a single list-value that is the union of all list-values passed to the
L
parameter.
If X
is N/A, the result is N/A.
Example
This example demonstrates how to use unlst(L1 L2...LN)
to create a single
list out of two lists. Notice that, unlike jnlst(L1 L2...LN)
,
unlst(L1 L2...LN)
eliminates duplicate values in the resultant
list-value.
<block name="list_funs" list_a="{lst('1' '2' '3' '4')}" list_b="{lst('1' 'a' 'b' 'c' 'd')}"> <base table="default.lonely"/> <willbe name="union" label="Union" value="'{unlst(@list_a @list_b)}'"/> </block>
The output from the unlst(L1 L2...LN)
function as used above:
Note how 1 appears only once in the resultant list-value.